Date:         Tue, 2 Nov 1999 07:26:29 -0500
Reply-To:     john_iwaniszek@worldnet.att.net
Sender:       "SAS(r) Discussion" <SAS-L@LISTSERV.UGA.EDU>
From:         John Iwaniszek <john_iwaniszek@WORLDNET.ATT.NET>
Organization: AT&T WorldNet Services
Subject:      Re: sum(of...... doesn't work
Content-Type: text/plain; charset=us-ascii

You can't evaluate only part of an expression in if-then statements, you
have to evaluate the whole thing.  Just remember, the if-then statement
evaluates the whole expression, not just some of it.  Pick which part of

s{(7*i)-6}-s{i*7}

you want to use, put it in the statement and then lose the sum() function.

John

Jeremy Bassett wrote:

> Can anyone tell me why the sum(of arr{<exp>} - arr{exp}) doesn't work
>
> This:
>
> %let stw_parm = 3;
>
> data test(keep = show1  - show12 subject stw1 - stw12 sympt1 - sympt84);
>   set in002.symp002;
>   by subject;
>   array o{12} show1  - show12;
>   array w{12} stw1   - stw12;
>   array s{84} sympt1 - sympt84;
>   do i = 1 to 12;
>     o{i} = sum(of s{(7*i)-6}-s{i*7});
>     if sum(of s{(7*i)-6}-s{i*7}) > &stw_parm then w{i} = 1;
>     else                                              w{i} = 0;
>   end;
> run;
>
> gives this ERROR:
>
> 350  data test(keep = show1  - show12 subject stw1 - stw12 sympt1 -
> sympt84);
> 351    set in002.symp002;
> 352    by subject;
> 353    array o{12} show1  - show12;
> 354    array w{12} stw1   - stw12;
> 355    array s{84} sympt1 - sympt84;
> 356    do i = 1 to 12;
> 357      o{i} = sum(of s{(7*i)-6}-s{i*7});
>                                  -
>                                  78
> 358      if sum(of s{(7*i)-6}-s{i*7}) > &stw_parm then w{i} = 1;
>                              -
>                              78
> 359      else                                              w{i} = 0;
> 360    end;
> 361  run;
>
> ERROR 78-322: Expecting a ','.
>
> NOTE: The SAS System stopped processing this step because of errors.