Date:         Fri, 25 Jun 1999 14:28:26 -0700
Reply-To:     "Karsten M. Self" <kmself@IX.NETCOM.COM>
Sender:       "SAS(r) Discussion" <SAS-L@LISTSERV.UGA.EDU>
From:         "Karsten M. Self" <kmself@IX.NETCOM.COM>
Organization: Self Analysis
Subject:      Fileref based on fileref pointing to directory?
Content-Type: text/plain; charset=us-ascii

Quickie, the obvious answer isn't right.

Is there a way to define a fileref based on an existing fileref in an
easy manner?  In this case, I've got a report fileref REP which points
to a directory where standard reports are filed.  To write my report I'd
do:

data _null_;
    set stuff;
    file REP("myreport.txt");
    put /* coolstuff */ ;
    run;

I'd like:

filename myreport REP("myreport.txt");


...but it doesn't work.

I can extract paths with SCL functions, is that the only option?

Details:  6.12/Unix.
--
Karsten M. Self (kmself@ix.netcom.com)
    What part of "Gestalt" don't you understand?

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