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Date:         Wed, 5 May 1999 11:40:05 -0400
Reply-To:     bill_droogendyk@DOFASCO.CA
Sender:       "SAS(r) Discussion" <SAS-L@UGA.CC.UGA.EDU>
From:         "W. Droogendyk" <bill_droogendyk@DOFASCO.CA>
Subject:      Re: reading data with the date format.
Comments: To: PapanikolaouP@CARDIFF.AC.UK
Content-Type: text/plain

Panos:

depending on the format of the 3 variables that you have, the mdy function may be all that you need e.g.

date=mdy(month,day,year)

It will then be a sas date value which you can format in any way you wish.

hth

W. (Bill) Droogendyk Quality Systems, Dofasco Inc. Hamilton, Ontario, Canada

Voice: 905 548 7200 x3359 Fax: 905 548 4007 email: <mailto:bill_droogendyk@dofasco.ca> bill_droogendyk@dofasco.ca

-----Original Message----- From: Panos PAPANIKOLAOU [SMTP:PapanikolaouP@CARDIFF.AC.UK] Sent: Wednesday, May 05, 1999 12:16 To: SAS-L@UGA.CC.UGA.EDU Subject: Re: reading data with the date format.

Dear All,

I have three distict variables each of those indicates the day, the month and the year of an event such as the admission to the hospital.

I want to create a new variable which will be such as:

day-month-year.

That is, I want SAS to read this variable with the date format.

One thought is to do in two steps by using the trim function. First, you create a new variable for day and month such as:

X=day||trim(month) ; you can then repeat this step for year and thus creating a new variable Y, ie., Y=X||trim(year) ;

I do not know whether or this is the right course of action. Equally, I am not sure how I would read this new variable in the date format. That is, how would i have SAS to read Y in date format.

I would appreciate if I would have comments and ideas on how to proceed, please.

Thank you very much indeed for taking the time to consider my request. I look forward to hearing from you.

Regards Panos Papanikolaou.


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