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Date:         Tue, 21 Jan 1997 09:57:00 -0500
Reply-To:     Dave_Mabey_at_RDA8POSTOFFICE1%RDCCMAIL%READERSDIGEST@RMAIL.COM
Sender:       "SAS(r) Discussion" <SAS-L@UGA.CC.UGA.EDU>
From:         Dave_Mabey_at_RDA8POSTOFFICE1%RDCCMAIL%READERSDIGEST@RMAIL.COM
Subject:      comm1-comm6 & SQL COALESCE function
Content-type: text/plain; charset=US-ASCII

New Forward Item:

---------------------------- Forwarded with Changes ----------------------- ---- From: Dave Mabey at RDA8POSTOFFICE1 Date: 1/17/97 2:36PM To: SAS-L@VM.MARIST.EDU@INTERNET at RDNOTES To: j_weedon@ESCAPE.COM@INTERNET at RDNOTES Subject: Re[2]: comm1-comm6 problem --------------------------------------------------------------------------- ----

New Text Item: Re: comm1-comm6 problem

Paul Kent at SAS Institute points out that the COALESCE function (SAS Guide to the SQL Procedure page 161) can be used to find the first non-missing value in a list of arguments. If one, and only one, "comm" has a valid code while the rest have missing values, then the following may be the simplest way to proceed.

PROC SQL; select coalesce(comm1,comm2,comm3,comm4,comm5,comm6) as index, count(*) from comfile group by index;

______________________________ Reply Separator________________________________

On Thu, 16 Jan 1997 08:51:23 -0500, Lisa Bastian <eagle89@EROLS.COM> wrote:

>I have a total of about 67 codes (numeric), any of which can be found >among six consecutive fields (comm1 comm6), although for each >observation, a code can only show up once. Is there any "easy" way to >count the occurrence of each individual code? ie., without an array and >a bunch of "if" statements? Thanx.


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