| Date: | Thu, 2 Jan 1997 16:33:25 +0200 |
| Reply-To: | Dvora Zomer <epid04@POST.TAU.AC.IL> |
| Sender: | "SAS(r) Discussion" <SAS-L@UGA.CC.UGA.EDU> |
| From: | Dvora Zomer <epid04@POST.TAU.AC.IL> |
| Subject: | Re: They can not answer this in the SPSS Group can SAS people |
|
| In-Reply-To: | <32C83204.3051@barra.com> |
| Content-Type: | TEXT/PLAIN; charset=US-ASCII |
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I just want to add that it is possible to identify the unique odd
ball out of 13 ones.
Ilya Novikov
On Mon, 30 Dec 1996, Mark Covello wrote:
> > Problem
> >
> > >>>You Have 12 balls.
> > >>>Identical to the eye
> > >>>11 balls have identical weights
> > >>>1 ball is either heavier or lighter
> > >>>You have a balance scale
> > >>>You can take 3 measures
> > >>>How can you identify the odd ball
> > >>>
>
>
> I'm sorry; I know I should ignore this post, but
> I just can't. Here goes for the glory of SAS-L
> and to show that we watch more Columbo than SPSS
> byteheads:
>
> Split balls into 3 groups of 4 each call them
> A1-A4
> B1-B4
> C1-C4
>
> Weigh 1: A1-A4 vs B1-B4
> balance:
> ===> bad ball is in C1-C4
> weigh 2: C1, C2 vs A1,A2
> balance:
> ====> bad ball is C3 or C4
> weigh 3: C3 vs A1
> Balance:
> bad ball is C4
> Not Balance:
> Bad Ball is C3
> weigh 2: C1, C2 vs A1,A2
> Not balance:
> ====> bad ball is C1 or C2
> weigh 3: C1 vs A1
> Balance:
> bad ball is C2
> Not Balance:
> Bad Ball is C1
>
> That takes care of alloutcomes in which the first weighing
> is in balance
>
> Next suppose:
> Weigh 1: A1-A4 vs B1-B4
> Not balance:
> ======> bad ball is in A1-A4,B1-B4
> Note direction of imbalance(for sake of explanation
> say A1-A4 is heavier than B1-B4, but the argument
> works equally as well in the other direction)
> Weigh 2: A1,A2,A3,B1 vs C1-C3,A4
> Not Balance in same direction (ie A1,A2,A3,B1 is heavier):
> =====> bad Ball is in A1, A2, A3 AND bad ball is heavier
> Weigh 3: A1 vs A2
> Balance:
> ====> bad ball is A3
> Otherwise
> Bad ball is heavier of A1, A2
> Not Balance in other direction (ie A1,A2,A3,B1 is lighter):
> =====> bad ball is in B1(lighter), A4(heavier)
> Weigh 3: B1 vs C1
> Balance:
> bad ball is A4
> Otherwise
> Bad ball is B1
>
>
> The remaining cases all occur when weigh 2 ends in balance:
>
> Weigh 2: A1,A2,A3,B1 vs C1-C3,A4
> Balance:
> =====> bad ball is in B2, B3, B4 and bad ball is lighter
> Weigh 3: B2 vs B3
> Balance:
> =====> B4 is bad
> Not balance:
> =====> the lighter ball of B2, B3 is bad
>
>
> I think that covers all possible outcomes.
>
> I hope someone gets extra credit for this. I solved
> this in a graduate Probability course about 10 years
> ago and I still took about 1/2 hour to come up with the answer
> now.
>
>
>
> --
> ********************************************************
> Mark S. Covello
> Programming Consultant
> current assigment:
> Barra
> Berkeley, California
>
> The views expressed in this post do not necessarily
> represent the views of Barra.
>
> "At the end we preferred to travel all night,
> Sleeping in snatches,
> With the voices singing in our ears, saying
> That this was all folly."
>
> T. S. Eliot
> << The Journey of the Magi >>
>
> ********************************************************
>
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