Date: Thu, 16 Jun 2011 11:25:59 -0500
Reply-To: "Data _null_;" <iebupdte@GMAIL.COM>
Sender: "SAS(r) Discussion" <SAS-L@LISTSERV.UGA.EDU>
From: "Data _null_;" <iebupdte@GMAIL.COM>
Subject: Re: PROC SUMMARY calculating _TYPE_.
In-Reply-To: <BANLkTin51HeSr5OpLF3FtZmnbx31m+UQCA@mail.gmail.com>
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On Thu, Jun 16, 2011 at 10:19 AM, Joe Matise <snoopy369@gmail.com> wrote:
> Not sure where you're getting at here.
I'm just trying to gather information from folks with math skills.
I thought I would get a bigger response. But if I think about from
looking at the code written by my "colleagues" in Pharma most of them
don't CLASS statements in MEANS/SUMMARY they like to sort and use BY.
Or they don't know that SUMMARY has the median and use UNIVARIATE.
I see you are comfortable with powers of 2, me not so much. Actually
when I need to fiddle directly with the value of _TYPE_ I usually use
the CHARTYPE option. I could use '0101001' and not have to think too
hard.
With the introduction of the BINARY informat I can still keep my
thinking to a minimum if I need to know as in this case 41.
2337 data _null_;
2338 bdg=input('0101001',binary.);
2339 put bdg=;
2340 run;
bdg=41
Thanks for the reference to the paper Richard I had not seen that one.
On Thu, Jun 16, 2011 at 10:19 AM, Joe Matise <snoopy369@gmail.com> wrote:
> Not sure where you're getting at here. B*D*G would be _TYPE_=41 (1+8+32).
> I think there's a way to determine it programmatically but I usually just
> do the math by hand, or even just do the proc means and look if i'm feeling
> particularly lazy and it's not too many lines :)
>
> -Joe
>
> On Thu, Jun 16, 2011 at 10:13 AM, Data _null_; <iebupdte@gmail.com> wrote:
>>
>> Say for
>>
>> CLASS A B C D E F G;
>>
>> How would YOU determine the value of _TYPE_ for the B*D*G conbinations.
>>
>> I know TYPES B*D*G; will output the records of interest but I want to
>> know how YOU would calculate _TYPE_.
>
>
