|Date: ||Wed, 12 Jan 2011 15:17:29 -0500|
|Reply-To: ||"Bian, Haikuo" <HBian@FLQIO.SDPS.ORG>|
|Sender: ||"SAS(r) Discussion" <SAS-L@LISTSERV.UGA.EDU>|
|From: ||"Bian, Haikuo" <HBian@FLQIO.SDPS.ORG>|
|Subject: ||Re: Easy macro comparison|
|Content-Type: ||text/plain; charset="iso-8859-1"|
Oh, if you are interested, there are numerous function available at your service: find(), findw(), or index etc.
If (find("&tablist.", "&tab." )) then do;
From: SAS(r) Discussion [mailto:SAS-L@LISTSERV.UGA.EDU] On Behalf Of William Krause
Sent: Wednesday, January 12, 2011 3:03 PM
Subject: Re: Easy macro comparison
Thanks, That worked.
--- On Wed, 1/12/11, Jack Clark <firstname.lastname@example.org> wrote:
From: Jack Clark <email@example.com>
Subject: RE: Easy macro comparison
To: "William Krause" <wkrause2003@YAHOO.COM>, SAS-L@LISTSERV.UGA.EDU
Date: Wednesday, January 12, 2011, 1:57 PM
You would have to put quotes around your reference to &tab.
if "&tab." in (&tablist.) then do;
Without the quotes, &tab resolves to mytable, which SAS will view as the
name of a data step variable (instead of a character constant).
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From: SAS(r) Discussion [mailto:SAS-L@LISTSERV.UGA.EDU] On Behalf Of
Sent: Wednesday, January 12, 2011 2:51 PM
Subject: Easy macro comparison
I have two macro variables:
&tab which contains a name of a table as mytable
&tablist which contains a list of table names as
In a data step, how would I compare &tab to the &tablist
in order to find mytable.
data test ;
set intest ;
if &tab in (&tablist) then do ;
if id = '1' then delete ;
Id of 1 exists in intest.
mytable is in the list of table in &tablist.
I would expect that the row with id of 1 would be delete therefore
my dataset would have 1 less obs.
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