Date:         Wed, 12 Nov 2008 11:13:54 -0600
Reply-To:     "./ ADD NAME=Data _null_," <iebupdte@GMAIL.COM>
Sender:       "SAS(r) Discussion" <SAS-L@LISTSERV.UGA.EDU>
From:         "./ ADD NAME=Data _null_," <iebupdte@GMAIL.COM>
Subject:      Re: Time interval
Comments: To: Allen Ziegenfus <aziegenfus@anaxima.com>
In-Reply-To:  <001701c944e7$df0b8ca0$1e02a8c0@SIRIUS.ANAXIMA.COM>
Content-Type: text/plain; charset=ISO-8859-1

On 11/12/08, Allen Ziegenfus <aziegenfus@anaxima.com> wrote:
> Couldn't you just subtract the two and divide by 60 or am I missing the
> point here?

Yes because the units are not seconds for example 1337 is not in
seconds units it is 49020 seconds.

210  data _null_;
211     a=1224;
212     b=1337;
213     c = b - a;
214     aT = input(put(a/1e2,5.2),time.);
215     bT = input(put(b/1e2,5.2),time.);
216     dT = bT - aT;
217     dM = dT / 60;
218     put 'NOTE: Results' @;
219     put (_all_)(/= 'NOTE- ');
220
221     *format aT bT time. dt mmss.;
222     run;

NOTE: Results
      a=1224
      b=1337
      c=113     *** this is not 73 as it should be;
      aT=44640
      bT=49020
      dT=4380
      dM=73


>
> -----Ursprüngliche Nachricht-----
> Von: SAS(r) Discussion [mailto:SAS-L@LISTSERV.UGA.EDU] Im Auftrag von Sid N
> Gesendet: Mittwoch, 12. November 2008 17:37
> An: SAS-L@LISTSERV.UGA.EDU
> Betreff: Time interval
>
> I am trying to find the difference (in minutes) between two times which are
> in the format hhmm (24-hr format). For example, the difference between 1224
> and 1337 should result in 73 minutes.
>
> Is there a function in SAS that can be used directly?
>
> Thank you for your attention.
>
> Sid
>