On Sat, 6 Sep 2008 12:25:16 -0700, hg448@YAHOO.COM (hua gang) wrote:

>Sorry for not including complete program, so I sent again. > >Thanks for reply, Dan. > >I used the following to compute the difference between yearsly dates, >only my first date variable, "date_base" has different format like, 03JUN08. >Because of it, the computation didn't work. Once I got ride of date_base," >and datedif0 it worked perfectly. So, this is the reason for me to try to >convert "date_base", but I can't find a way to do it right away.

Don't you think it would help if you told us what went wrong?

> >Thanks again for your help. > >Hua > > >arraydc{4} date_base dateyear_1 dateyear_2 date_year3; >arraydd{4} daydif0 daydif1 daydif2 datedif3; > >seth4;

What kind of statement is this.

>doi=2to4;

Maybe you should cut and paste your code rather than retyping it.

> last_date=.; > j=i; > dd{i}=.; > dountil((last_date ne .) or (dc{i} = .)); > j=j-1;

Horizontal white space is free and make your code much easier to read.

> ifdc{j} ne .thenlast_date=j; > elseifj=1thenleave; > end; > >/* only need to do a diff here since SAS dates count days from a set point */ > ifnmiss(last_date,dc{i})=0thendd{i}=dc{i}-dc{last_date}; >end; > >dropi j; *last_date; > >run;

-- Remove del for email