Date: Tue, 23 Oct 2007 09:48:54 -0400
Reply-To: "Sridhar, Nagakumar" <nagakumar.sridhar@SPCORP.COM>
Sender: "SAS(r) Discussion" <SAS-L@LISTSERV.UGA.EDU>
From: "Sridhar, Nagakumar" <nagakumar.sridhar@SPCORP.COM>
Subject: Re: Newbie ...heed help
In-Reply-To: A<BAY123-W329E9E9A66CD60FFEDED18DE9B0@phx.gbl>
Content-Type: text/plain; charset="us-ascii"
Toby:
I think it needs to be:
proc sort data=have;
by seq date;
run;
data have;
set have;
by seq date;
if first.seq;
run;
Without the date in the sort and set statements, you'd have:
1 0123 oct 1 abc 1234 abc123
2 0125 oct 15 abc 1124 abc123
3 0128 oct 1 abc 1234 abc13f
4 0426 oct 12 abc 4576 abc978
Which is NOT what he's looking for..
Maybe I'm wrong (I have been wrong before)
Kumar
-----Original Message-----
From: SAS(r) Discussion [mailto:SAS-L@LISTSERV.UGA.EDU] On Behalf Of
toby dunn
Sent: Tuesday, October 23, 2007 9:36 AM
To: SAS-L@LISTSERV.UGA.EDU
Subject: Re: Newbie ...heed help
I got a little happy hitting the send button made a correction below:
Proc Sort
Data = Have ;
By Seq Date ;
Run ;
Data Need ;
Set Have ;
By Seq ;
If First.Seq Then Output ;
Run ;
Toby Dunn Compromise is like telling a lie, it gets easier and easier.
Each compromise you make, that becomes your standard. Perfection doesnt
exist, once you reach it, its not perfect anymore. It means something
else.> Date: Tue, 23 Oct 2007 00:06:25 -0700> From: frytz.d@GMAIL.COM>
Subject: Newbie ...heed help> To: SAS-L@LISTSERV.UGA.EDU> > I want to
filter a dataset by removing entry with same sequence number> but older
data.> > sample:> > seq# date data1 data2 data2> 0123 oct 1 abc 1234
abc123> 0426 oct 12 abc 4576 abc978> 0123 oct 18 jfk 1234 abde23> 0128
oct 1 abc 1234 abc13f> 0426 oct 21 klm 9923 99c12g> 0125 oct 15 abc 1124
abc123> 0128 Sep 15 abc 1234 abc123> > > output should be> > seq# date
data1 data2 data2> 0123 oct 18 jfk 1234 abde23> 0128 oct 1 abc 1234
abc13f> 0426 oct 21 klm 9923 99c12g> 0125 oct 15 abc 1124 abc123> > >
...please advise ....> The simplier the better
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