Where's Joe when ya need him???

;-)

Kumar

-----Original Message----- From: SAS(r) Discussion [mailto:SAS-L@LISTSERV.UGA.EDU] On Behalf Of Richard A. DeVenezia Sent: Wednesday, January 03, 2007 8:57 AM To: SAS-L@LISTSERV.UGA.EDU Subject: Re: Help needed for histogram

Subhransu wrote: > Dear Friends > > I am writing a piece SCL code which is producing librarires , datasets

> in it and all the variables(columns). the dataset also can be seen in > a table viewer , also we can choose the variables in it. > > The problem i am facing is while creating a histogram out of the data > in the dataset, its not allowing me to do it at the runtime. > > for example : > > i am selecting a library, then the dataset in it. The dataset is > visible in the table viewer. I am selecting 3 variable for the input > to histogram.

What kind of LOG messages are you getting? What procedure or object are you using to create the histogram?

The viewer may have a table lock on the data, preventing the procedure or object from concurrently accessing the table.

This scenario _does_ allow a histogram and its data to be viewed simultaneously. -------------------------------------- Create a frame that contains a table viewer control, a sas data set model, a histogram control, and a push button control. -------------------------------------- pushbutton1: table = opensasfiledialog('data view'); sasdataset1.table = table; histogram1.dataset = table; histogram1.xvariable = 'age'; return;

-------------------------------------- click the button and select sashelp.class.

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