Date:         Thu, 26 Jan 2006 19:15:44 -0500
Reply-To:     SUBSCRIBE SAS-L Peter Yeltzin <peter98@INTERNODE.ON.NET>
Sender:       "SAS(r) Discussion" <SAS-L@LISTSERV.UGA.EDU>
From:         SUBSCRIBE SAS-L Peter Yeltzin <peter98@INTERNODE.ON.NET>
Subject:      Re: Histogram in IML

With a little playing around i realised this works

data match;
length name $20;
if _N_=1 then do;
 declare hash hh(dataset: "work.small");
  rc = hh.defineKey('name');
  rc = hh.defineDone();
 end;
set big;
rc = hh.find();
if (rc NE 0) then output;
run;