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Patrice
If Venky's pathname doesn't work, try the filename option on the infile
statement as in the snipped below.
length file $ 50;
infile txt filename=file lrecl=80 truncover;
informat txt $72.;
input txt $ 1-72;;
source=file;
Note two items
1) you need to define a character variable to hold the filename info
and
2) you need to stick this info somewhere, I used a new variable called
Source, because the variable file is temporary.
Nat Wooding
Patrice Bourdages
<Patrice.Bourdage To: SAS-L@LISTSERV.UGA.EDU
s@IAAH.CA> cc:
Sent by: "SAS(r) Subject: How to get directory from LIBNAME or equivalent
Discussion"
<SAS-L@LISTSERV.U
GA.EDU>
09/09/05 10:30 AM
Please respond to
Patrice.Bourdages
Hello to you all...
Once again, I'm asking the strangest question...
Is there a way to extract / get / extirpate the directory from a libname
statement ???
Here's an example of what I'm looking for :
libname Test1 "/data1/mergedata";
I need to know, further down in some other program, where the libname "
Test1 " points to as directory with something like :
Extract = GetDirectory( "Test1" )
Extract would then contain "/data1/mergedata".
The problem here is that the libname statement assigns standard librairies
depending if we are in DEV or PROD mode. So Test1 will point to
/data1/mergedata in PROD mode and /data2/mergedata in DEV mode.
Hope somebody has an answer to this one... I've looked into documentation
for the past hour and couldn't find anything of interest regarding this
matter...
TIA for any reply.
Sincerely yours,
Patrice Bourdages :-)
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