With that solution I get

%macro ptype; %do i=1 %to 6; proc means data = cli_pro(where =(ptype="&&ptype&i")) noprint; by CLIENT; VAR status BALANCE_1 BALANCE_2 BALANCE_3; output out=cli_&&ptype&i(drop=_freq_ _type_) sum(balance_1)=&&ptype&i; %end; run; %mend; %macro ptype;

AVISO: No se ha resuelto la referencia simbólica aparente PTYPE1AMTEMO.

ERROR 22-322: Error de sintaxis, se espera uno de los siguientes: un nombre, ;, /, CSS, CV,

IDGROUP, IDGRP, KURTOSIS, LCLM, MAX, MAXID, MEAN, MEDIAN, MIN, MINID, N, NMISS,

OUT, P1, P10, P25, P5, P50, P75, P90, P95, P99, PROBT, Q1, Q3, QRANGE, RANGE,

SKEWNESS, STDDEV, STDERR, SUM, SUMWGT, T, UCLM, USS, VAR.

ERROR 202-322: La opción o el parámetro no se reconoce y se pasará por alto .

"Howard Schreier <hs AT dc-sug DOT org>" <nospam@HOWLES.COM> escribió: You are confusing character expressions and code. Try

output out=cli_&&ptype&i(drop=_freq_ _type_) sum(balance_1)=&&ptype&i.amtemo;

Contrast with

newvar = "&&ptype&i" || "amtemo" ;

On Fri, 2 Sep 2005 01:46:57 +0200, Miguel de la Hoz wrote:

>Hello: > >I am trying to run this sentence in order to get new variables, I write &&ptype&i||"amtemo" but it is not working as should do, do you have any idea, please??? > >%macro ptype; > >%do i=1 %to 6; > >proc means data = cli_pro(where =(ptype="&&ptype&i")) noprint; > >by CLIENT; > >VAR status BALANCE_1 BALANCE_2 BALANCE_3; > >output out=cli_&&ptype&i(drop=_freq_ _type_) sum(balance_1) =&&ptype&i||"amtemo"; > >%end; > >run; > >%mend; > > > > >--------------------------------- > >Correo Yahoo! >Comprueba qué es nuevo, aquí >http://correo.yahoo.es

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Correo Yahoo! Comprueba qué es nuevo, aquí http://correo.yahoo.es