first I have to say that I am not a statistican but only a biologist, who
knows a little about statistics.
As far as I know I would give you the following answere to your question:
If you conduct a t-test (two-sided and you get a p value of lets say p =
0.01 - I did not calculate your data - it is only an example) you would get
a value of p = 0.005 for a one sided approach. The p for a one-sided test
is always half the p of a two sided test. But now you have to look in which
direction there is a deviation from the expected mean! In your case the p
value, which is half the p-value you calculated for two-sided gives the
probability that the blood preasure is smaller than the baseline. This is
the other direction of that one you wanted to test! So you'll need to
calculate the p-value for the other side. In theorie the p value right
sided (lets call it pr) is always 1 - the p value left sided (lets call it
pl) for a given hypothesis:
pr = 1 - pr
Or in other words: The total probabilities under a normal distribution is
So, you only have to do this calculation. For the data I gave you in my
example above you would get p(other side) = 1 - 0.005 = 0.995
This is clearly not significant. You can do the same with your data.
But first of all I would like to ask you the following question:
You have got 12 data-pairs (if I counted it right) and in none of them you
got a change in the direction you expected but to the other side. Do you
really think that any statistics is necessary to verify your findings?
Statistical calculations are senseful - but only if it is not clear by
simply looking at the data if there is an effect or not.
Hope I could help you a little and keep in mind: I am not a statistican.
Maybe a statistican at this forum could verify my words or say that I am
On Tue, 8 Jun 2004 15:28:00 +0000, statto stats <statto_22@HOTMAIL.COM>
>I'm trying to anayse %change from baseline data.
>input SBPbefore SBPafter @@;
>per_change=SBPafter/SBPbefore - SBPbefore/SBPbefore;
>130 100 134 100 130 100 138 100 140 100 138 100 140 100 135 100 136 100 130
>100 136 100 137 100 ; run;
>As you can see most people have a considerable reduction in their SBP
>(Systolic Blood Pressure).
>However, I suspected there to be an increase in SBP and so set about
>intending to analyse the data using a one-sided t-test with the following
>H0: mean %change < 0.25
>H1: mean %change >=0.25
>I still hop to use these hypothesis. Using proc ttest
>proc ttest data=pressure alpha=0.05 h0=0.25 ;
>or proc univariate
>proc univariate data=pressure alpha=0.025 mu0=0.25 cibasic cipctlnormal
>normal plots plotsize=40;
>probplot per_change /normal(mu=est sigma=est) pctlminor;
>inset mean std / format=3.0 header='Normal Parameters' position=(95,5)
>However this actually test the hypotheses
>H0: mean %change = 0.25
>H1: mean %change not equal to 0.25
>And gives a significant p-value?
>Does anybody know how I can test my original hypothesis? And get a
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