LISTSERV at the University of Georgia
Menubar Imagemap
Home Browse Manage Request Manuals Register
Previous (more recent) messageNext (less recent) messagePrevious (more recent) in topicNext (less recent) in topicPrevious (more recent) by same authorNext (less recent) by same authorPrevious page (February 2004, week 2)Back to main SAS-L pageJoin or leave SAS-L (or change settings)ReplyPost a new messageSearchProportional fontNon-proportional font
Date:         Mon, 9 Feb 2004 08:36:32 -0500
Reply-To:     Paige Miller <paige.miller@KODAK.COM>
Sender:       "SAS(r) Discussion" <SAS-L@LISTSERV.UGA.EDU>
From:         Paige Miller <paige.miller@KODAK.COM>
Organization: Eastman Kodak Company
Subject:      Re: statistical analysis problem
Content-Type: text/plain; charset=us-ascii; format=flowed

conjecture wrote: > I've two groups of people, I try to compare the occupation between two > groups. > > eg > Police Cook Accountant > A 1000 200 500 > B 1500 150 600 > > The distribution is > Police Cook Accountant > A 59% 12% 29% > B 67% 7% 27% > > I try to compare the percentage, say Police, 59% vs 67% using normal > test.

I would not use a normal test on this data. The data are not normally distributed.

Perhaps you meant that you are using a normal approximation to a binomial test. If that is what you are doing, that is probably fine in this case.

> Should I conclude the two group are different when we find the test is > significant? I don't want to use chi square test because it is not as > detailed as the normal test to test all the occupation. Agree??

I don't understand your objection to chi-squared. Chi-squared would be my first choice as a test to compare groups A and B across the three occupations.

-- Paige Miller Eastman Kodak Company paige dot miller at kodak dot com http://www.kodak.com

"It's nothing until I call it!" -- Bill Klem, NL Umpire "When you get the choice to sit it out or dance, I hope you dance" -- Lee Ann Womack


Back to: Top of message | Previous page | Main SAS-L page