Date:         Wed, 23 Jul 2003 05:21:48 +0000
Reply-To:     sashole@bellsouth.net
Sender:       "SAS(r) Discussion" <SAS-L@LISTSERV.UGA.EDU>
From:         Paul Dorfman <paul_dorfman@HOTMAIL.COM>
Subject:      Re: Conditional character concatenation
Comments: To: MurffMJ@LDSCHURCH.ORG
Content-Type: text/plain; format=flowed

Mike,

I frankly think that SAS-centric-wise, Ravi's offer is the cleanest... but
agree with Jack that you may really want a character-to-character mapping
without a double type conversion, in which case I wonder if a solution
simpler than that which follows can be obtained:

   newstr = "000000" ;
   substr (newstr, 1, length(oldstr)) = oldstr ;

It assumes that the input string OLDSTR has been LEFTed, else replace all
occurrences OLDSTR by LEFT(OLDSTR).

Kind regards,
================
Paul M. Dorfman
Jacksonville, FL
================

>From: Michael Murff <MurffMJ@LDSCHURCH.ORG>
>
>Dear SAS-L,
>
>I want to conditionally concatenate zeros onto the end of a string. The
>condition is how many characters exist to the _right_ of the decimal. I
>need all values to have zeros out to three decimal places IF no other
>integer occupies that space; else the variable should remain unchanged. For
>instance,
>
>3.5 --> 3.500
>3.51 --> 3.510
>3.511--> 3.511
>12.1-->12.100
>12.11 --> 12.110
>12.111-->12.111
>
>I've used the index function to append characters on the front of string,
>but his seems like the opposite problem. Hopefully this problem is not so
>trivial that it fails to illicit responses.
>
>Thanks,
>
>Mike Murff
>SLC, Utah

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