The OTHER SAS User <sas@SDAC.HARVARD.EDU> wrote: > Proc iml; > ... > A=diag(Pi)*(I(&n)-diag(Pi)); **Here Pi is a 1 times 1440 vector.

But what your colleague is doing in this line requires working with (at least one) 1440x1440 matrix! At 8 bytes per number, that's 16,588,800 bytes. Per matrix. Which is really wasteful here, since this can be done in a less computational manner. You're only working with the diagonal, so you cna do this as a vector calc, instead of a full matrix calc.

> And getting the following error: > > Worksize = 262128 > Symbol size = 262128 > NOTE: IML Ready > ERROR: (execution) Unable to allocate sufficient memory. At least 16588832 more > . . .

So now you can see where that '16588832' could be coming from.

You may want to try starting PROC IML with a big WORKSIZE= value: proc iml worksize=100000; would request 100,000 K available for the WORKSIZE option. But IML is supposed to allocate this stuff dynamically, so I have to wonder if your colleague hasn't already clogged up all possible RAM before trying to compute 'A'. So here are a few PROC IML tips you might suggest to your IML'er:

Use FREE to free matrices you're no longer using. Use STORE if you have a large matrix you won't need for a bit, and then FREE up its storage space. Re-design your matrix calcs so you don't need such massive matrices.

I personally recommend #3 there.

HTH, David -- David Cassell, CSC Cassell.David@epa.gov Senior computing specialist mathematical statistician