| Date: | Sun, 5 Jan 2003 17:26:08 +0000 |
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| Reply-To: | John Whittington <John.W@MEDISCIENCE.CO.UK> |
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| Sender: | "SAS(r) Discussion" <SAS-L@LISTSERV.UGA.EDU> |
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| From: | John Whittington <John.W@MEDISCIENCE.CO.UK> |
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| Subject: | Re: what does this mean? |
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| In-Reply-To: | <E18VBm4-0002hh-00@coumxnn01.netbenefit.co.uk> |
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| Content-Type: | text/plain; charset="us-ascii"; format=flowed |
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At 14:23 05/01/03 +0000, Roland wrote:
>"Andy Walsh" <aw@somelab.nospam.com> wrote in message
>news:3e183a2b$0$7976@echo-01.iinet.net.au...
> > I am converting SAS code output to C (I know nothing about SAS).
> > What does the following line of code mean? (surely should be easy for
> > experts!)
> >
> > if ( RV > .z ) goto N0_5;
> > I just don't get the .z part...
>
>It looks as though something has gone wrong in the conversion, as far as I
>can tell. The ".z" will have the effect of a missing value (just ".") no
>matter if the "z" is there or not. So the effect is that if RV has been
>given a value that is not missing then branch to the NO_5 label in the code.
Roland, I think you need to read up about SAS 'special missing values'.
Kind Regards
John
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