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Dear Morris,
First of all (and to everyone posing problems to SAS-L): do not state a
subject like "question" or "help", because that is what it is about always.
Just describe your problem more to the point, e.g. "processing data and
lag".
Secondly, I do not understand what you would want to do with your first
problem. I can't see any logic in what you state on point of departure and
desired result.
Your second problem can be solved from within a macro by the following
lines, replacing your assignments of var 1 to var10:
%LOCAL I;
%DO I = 1 %TO 10;
var&I=lag&I(aa);
%END;
Regards - Jim.
--
Y. (Jim) Groeneveld, MSc IMRO TRAMARKO tel. +31 412 407 070
senior statistician, P.O. Box 1 fax. +31 412 407 080
senior data manager 5350 AA BERGHEM IMRO TRAMARKO: a CRO
J.Groeneveld@ITGroups.com the Netherlands in clinical research
My computer beeps when it complains; I complain when it beeps
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> -----Original Message-----
> From: Morris [SMTP:soaring-cato@YAHOO.COM.TW]
> Sent: Thursday, March 07, 2002 8:26 AM
> To: SAS-L@LISTSERV.UGA.EDU
> Subject: a simple question
>
> hi..everyone
> i have some problem in my report .can anyone tell me
> how to do,
>
> first problem is that i have two data set,average of
>
> var in first is inital value in second data set.
>
> ex.
> Obs var1
> 1 10
> 2 50
> 3 30
>
> average of var1 is 45
>
> then there is a new var3 in second(var2 is given)
>
> obs var2 var3
> 1 20 65...........20+45
> 2 55 120...........65+55
> 3 70 190...........120+70
>
> and do any efficient method to do this process?
>
>
> second is that i want some new variables("aa" is
> given)
> ex. var1=lag(aa);
> var2=lag2(aa);
> ....
> var10 =lag10(aa);
>
> and do any efficient method to do this process?
>
> Many thanks
>
> Sincerely
>
> Morris Hu
>
> -----------------------------------------------------------------
> < ¨C¤Ñ³£ Yahoo!©_¼¯ > www.yahoo.com.tw
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