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Shireen:
I'm assuming the 'set a;' statement is missing from the 'data f;' data step.
data f;
set a;
if p10 lt 0 or pf11 lt0 or pf12 lt 0 or pf13 lt 0 or pf14 lt 0 or pf14
lt 0 then output f;
run;
I was able to get the column headings to appear when I inserted "split='*'"
as an option:
e.g.
proc print data=f split='*'; /* note split = '*' */
label p1='lambda11'
p2='lambda21'
p3='lambda32'
p4='lambda42'
p5='lambda53'
p6='lambda63'
p7='phi21'
p8='phi31'
p9='phi32'
p10='delta1'
p11='delta2'
p12='delta3'
p13='delta4'
p14='delta5'
p15='delta6';
run;
-----Original Message-----
From: shireen p [mailto:shireenp@HOTMAIL.COM]
Sent: August 1, 2001 3:33 PM
To: SAS-L@LISTSERV.UGA.EDU
Subject: simple label &output
Hello,
Could some one help me with this simple problem. Any help is much
appreciated. Thank you.-Shireen
Data a;
input @1 p1 13. @14 p2 13. @27 p3 13. @40 p4 13. @53 p5 13. @66 p6 13./
@1 p7 13. @14 p8 13. @27 p9 13. @40 p10 13. @53 p11 13. @66 p12 13./
@1 p13 13. @14 p14 13. @27 p15 13.;
cards;
..
..
;
data f;
array td(6) p10-p15;
array ph(3) p7-p9;
do i=1 to 6;
if td(i) LT 0 then output f;
end;
/*(here I want only one output record if any one of the td(i)is LT 0 instead
of multiple records one for each negative variable)*/;
run;
data try;
set f;
proc print data=f;
label p1='lambda11'
p2='lambda21'
p3='lambda32'
p4='lambda42'
p5='lambda53'
p6='lambda63'
p7='phi21'
p8='phi31'
p9='phi32'
p10='delta1'
p11='delta2'
p12='delta3'
p13='delta4'
p14='delta5'
p15='delta6';
run;
/* why does the labels statement not work */;
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