Date:         Mon, 16 Jul 2001 11:53:33 -0600
Reply-To:     Jack Hamilton <JackHamilton@FIRSTHEALTH.COM>
Sender:       "SAS(r) Discussion" <SAS-L@LISTSERV.UGA.EDU>
From:         Jack Hamilton <JackHamilton@FIRSTHEALTH.COM>
Subject:      Re: how would you write..?
Comments: To: yeon_rhee@HOTMAIL.COM
Content-Type: text/plain; charset=us-ascii

You could use

   if z in ('A', 'B', 'C', 'D', 'E') then count + 1;

or

   if 'A' <= z <= 'E'

This last solution works only if the actual values you want to check for are in a sequence.  If you're on an EBCDIC system, only some sequences work as expected.  For example, on an IBM machine,

   if z in ('G', 'H', 'I', 'J', 'K', 'L');

is not the same as

   if 'G' <= z <= 'L';





--
JackHamilton@FirstHealth.com
Development Manager, Technical Group
METRICS Department, First Health
West Sacramento, California USA


>>> ywr1 <yeon_rhee@HOTMAIL.COM> 07/16/2001 7:16 AM >>>
in proc iml,

i would like to write program that counts how many elements in z
equat to either 'A','B','C' 'D' or 'E'

so i wrote,

z={'A' 'B' 'C' 'D' 'E' 'F' 'G' 'H'};
nc=ncol(z);
count=0;
do i=1 to nc;
 if z='A' | z='B' |z='C' | z='D' | z='E' then count=count+1;
end;

#from above statements, how can i avoid writing 'z=' 5 times?