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Date:         Fri, 4 May 2001 15:43:39 +0100
Reply-To:     John Whittington <John.W@MEDISCIENCE.CO.UK>
Sender:       "SAS(r) Discussion" <SAS-L@LISTSERV.UGA.EDU>
From:         John Whittington <John.W@MEDISCIENCE.CO.UK>
Subject:      Re: OT:  Aggregate preference measurement, disagreement index
Comments: To: kmself@IX.NETCOM.COM
In-Reply-To:  <E14sDYB-0004DS-00@relay1.netnames.net>
Content-Type: text/plain; charset="us-ascii"

At 17:50 24/04/01 -0700, Karsten M. Self wrote (in part):

>....This works relatively well, but it fails to take into account >variance in votes indicating possible differences of opinion, >controversiality, or other disagreement among moderators. Assuming six >moderations, all other things equal, I'd like to see: >(1, 1, 1, 5, 5, 5) rated higher than (3, 3, 3, 3, 3, 3), though they >both have the same mean.

Karsten, I haven't noticed any replies to this post of yours, so just a few thoughts.....

The problem there is that you would have to create a whole set of (essentially arbitrary) rules as regards what you wanted to be rated higher than what. The example you give is straightforward enough - but where, for example, would you want, say, (2,2,2,4,4,4) to stand in relation to, say, (1,1,4,4,4,4)? etc. etc. etc.

You could, I suppose, just generate arbitrary derived indices which had roughly the effect you wanted. For example, if you divided your mean by (range +1) or (SD+1) [the +1 to avoid division by zero problems], you'd get a figure which would be largest when there was least variability of the scores - but whether third parties would consider such a manipulated score as having any meaning is a different matter.

>I'd also like to indicate a stronger sense of certainty for more ratings >than fewer. (5) is less significant than (5, 5, 5, 5, 5), and may be >less significant than (5, 5, 5, 5, 4).

Again, you would have to (arbitrarily) decide upon your rules. I suppose the most dramatic extreme would be to use the sum of all available scores, rather than the mean - which would give figures of 5, 25 and 24 for your three examples, respectively. If you also divided by (range+1), as per above, they would then become 5, 25 and 12 respectively - but that is probably too 'violent' an adjustment for your needs - and, again, the figures might well not be considered meaniful by third parties.

Kind Regards,

John

---------------------------------------------------------------- Dr John Whittington, Voice: +44 (0) 1296 730225 Mediscience Services Fax: +44 (0) 1296 738893 Twyford Manor, Twyford, E-mail: John.W@mediscience.co.uk Buckingham MK18 4EL, UK mediscience@compuserve.com ----------------------------------------------------------------


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