Date: Thu, 11 Jan 2001 07:01:42 -0000
Reply-To: sashole@bellsouth.net
Sender: "SAS(r) Discussion" <SAS-L@LISTSERV.UGA.EDU>
From: Paul Dorfman <paul_dorfman@HOTMAIL.COM>
Subject: Re: Hi there!
Content-Type: text/plain; format=flowed
Jacinto,
As a matter of fact, you do not even need to organize an array for this
purpose due to SAS's ability to process lists. If I understand your task
correctly (there is a slight inconsistency in the explanation: in the second
record, mon_job4 appears to be the greatest, contrary to what you have
written), you are in need of finding the maximum amongst mon_job2-mon_job6,
compare that maximum to mon_job1, and find which is greater. But it is the
same as simply obtaining the maximum of mon_job1-mon_job6. The latter is
given by the expression
max_job = max (of mon_job1-mon_job6);
Kind regards,
=========================
Paul M. Dorfman
Jacksonville, Fl
=========================
>From: "'Jacinto (Jack) F. Mendoza'" <Goffmanjr@AOL.COM>
> Hello and happy new year! I seem to be at a dilemma with an >array.
>Here is the data lay out of certain variables:
>
>obs mon_job1 mon_job2 mon_job3 mon_job4 mon_job5 mon_job6
>1 3 6 9 12
>2 3 6 12 9...
>
>How do I create an array in which I can properly compare mon_job1 to
> >mon_job2 thru mon_job6? That is, how do I create an array in which I
> >can take the highest value of mon_job2 thru mon_job6 and use that >value
>(instead of the value utilized in mon_job1). For example, in >obs1
>mon_job4>mon_job1, hence I need to create a variable that takes >hold of
>the value of mon_job4; in obs2, I need the value mon_job3 >since it's
>greater than mon_job1 (and greater than mon_job1, mon_job2, >and mon_job4).
> I hope I'm explaining myself correctly. PLEASE HELP, >THANKS!-jfm
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