Thank you, Peter ... and Eva, and James, and Tom, and Koen, and David, and Bernard, and Ed, and whoever has sent me something after I push the "send" button. It really pays to have awake friends!

;) Mark

peter.crawford@db.com on 06/15/2000 10:22:40 AM

To: Mark K Moran/CSD/HQ/BOC@BOC

cc: SAS-L@listserv.uga.edu

Subject: Antwort: IF-THEN LOG ERROR

check out the character between '20320' and '20910' I should be a comma ',' but it is a dot '.' " '20320'.'20910' " Worth trying to fix this first

Datum: 15.06.2000 15:02 An: SAS-L@listserv.uga.edu

Antwort an: Mark.K.Moran@ccmail.census.gov

Betreff: IF-THEN LOG ERROR Nachrichtentext:

The following SAS 6.12 log shows the first error in a much longer program. I suspect the problem with the IF-THEN has to do with parentheses. The line overtop the 200 occurs directly lined up under the word "and" in line 288 (it got shifted when I cut and pasted into this email, but I hopefully have moved it back to the correct spot). I am wondering what the problem is. Maybe it would help if I woke up! :) Mark >>>>>>>>>>>>>>>> cpu time 0.89 seconds

283 284 Data WORK.WHIST(keep=id by1 by2 by3 weight bynum type1 type2 type3 item nvalue); 285 length BY2 $2; 286 set WORK.GIST; 287 Indicate = empt; 288 if ((bk IN ('20210','20220','20310','20320'.'20910','20920')) and (empt=2)) - 200 289 THEN by1='20A'; 290 /* IF (bk IN ('20210','20220','20310','20320','20910','20920')) */ 291 /* THEN by1=bk; */ 292 ELSE IF (bk IN ('20210','20220','20310','20320','20910','20920')) and (empt=1)) - 22

200 293 THEN by1='20B'; ---- 202 294 ELSE by1=substr(bk,1,3); ERROR: No matching IF-THEN clause. 295 by2=Indicate; 296 by3=other;