Date:         Tue, 6 Jun 2000 19:13:13 -0500
Reply-To:     O J Nwoha <nwohaj@SPECTRE.AG.UIUC.EDU>
Sender:       "SAS(r) Discussion" <SAS-L@LISTSERV.UGA.EDU>
From:         O J Nwoha <nwohaj@SPECTRE.AG.UIUC.EDU>
Subject:      Re: Converting Months to Year
Comments: To: Roger Barnes <Roger_Barnes@oz.sas.com>
In-Reply-To:  <2E8ACB34A778D311940400805F6500CDD651B8@wallaby.oz.sas.com>
Content-Type: TEXT/PLAIN; charset=US-ASCII

Thanks Roger:

It worked.

On Wed, 7 Jun 2000, Roger Barnes wrote:

> Date: Wed, 7 Jun 2000 09:51:09 +1000
> From: Roger Barnes <Roger_Barnes@oz.sas.com>
> To: 'O J Nwoha' <nwohaj@spectre.ag.uiuc.edu>, SAS-L@LISTSERV.UGA.EDU
> Subject: RE: Converting Months to Year
>
> This should do it:
>
> data tmp;
>       do time=1 to 48;
>               year=int((time-1)/12)+1;        /* this is the line you need
> */
>               output;
>       end;
> run;
>
> proc print data=tmp;
> run;
>
> > -----Original Message-----
> > From: O J Nwoha [mailto:nwohaj@SPECTRE.AG.UIUC.EDU]
> > Sent: Wednesday, 7 June 2000 9:46 AM
> > To: SAS-L@LISTSERV.UGA.EDU
> > Subject: Converting Months to Year
> >
> >
> > Dear Saslers:
> >
> > I have one variable named TIME that runs from 1 to 48.
> > I would like to convert to years where such that when time is 1 to 12,
> > year is 1. When time is 37 to 48 year is 4.
> >
> > Thanks in advance for your usual help.
> >